Cytron Technical Forum

Noobie WROTE:How to modify the product schematic to interface with PC using serial port DB9 instead of passing through UART then UC00A?

ober WROTE:

Noobie WROTE:How to modify the product schematic to interface with PC using serial port DB9 instead of passing through UART then UC00A?

You want to bypass using UC00A? In other words, is using conventional method, the RS232 DB9 serial port? Then you need to have a RS232 level shifter. try to search for MAX232 circuit. This might be helpful:


If you look carefully, MAX232 require four connection from microcontroller board: 5V, GnD, TX and RX which you can get it from the standard connector which originally UC00A being connected.

CODE: SELECT_ALL_CODE

char id1[]={"1234567890"},id2[]={"9876543210"};
         
j=0;
for(i=0;i<=9;i++){
     if(rfid[i]==id1[i]) j++;}   
//if all 10 digit rfid equal to 10 digit id1, j will equal to 10
if(j==10) user=1;

j=0;
for(i=0;i<=9;i++){
     if(rfid[i]==id2[i]) j++;}   
//if all 10 digit rfid equal to 10 digit id1, j will equal to 10
if(j==10) user=2;

lcd_goto(20);
send_string("Welcome ");
switch(user){
case 1: {send_string("Sam");break;}
case 2: {send_string("Max");break;}
default: {send_string("Alien");break;}
}


shahrul WROTE:You comparing 10 digit id and change into username

eg:

CODE: SELECT_ALL_CODE

char id1[]={"1234567890"},id2[]={"9876543210"};
         
j=0;
for(i=0;i<=9;i++){
     if(rfid[i]==id1[i]) j++;}   
//if all 10 digit rfid equal to 10 digit id1, j will equal to 10
if(j==10) user=1;

j=0;
for(i=0;i<=9;i++){
     if(rfid[i]==id2[i]) j++;}   
//if all 10 digit rfid equal to 10 digit id1, j will equal to 10
if(j==10) user=2;

lcd_goto(20);
send_string("Welcome ");
switch(user){
case 1: {send_string("Sam");break;}
case 2: {send_string("Max");break;}
default: {send_string("Alien");break;}
}