Cytron Technical Forum

Hello guys. Is it possible for me to use the output from the RF module as an input to the arduino. If its possible, how can it be done. I assumed the output from the Rf module is 5v, and i tried connecting it with a 10k, 220 ohm resistor and also without any resistors, but it was unsuccessful. can somebody help me please?

Show some photos of the connection, please. Also the code.

robosang WROTE:Show some photos of the connection, please. Also the code.

Fortunately i was able to solve the problem. I mistakenly connect the output from the RF module to ground. After solving that problem, another issue arised. I am able to interrupt the arduino (perform a simple led blinking task) using output signal from the rf module. But i need to return to a specific function after the interrupt is executed. Is it possible to do so? If possible, how can it be done?Thanks in advance!

Show us what you did, how can we imagine your code?

robosang WROTE:Show us what you did, how can we imagine your code?

CODE: SELECT_ALL_CODE

// Flag needs to be volatile if used in an ISR
volatile int buttonFlag = LOW;
int pin1 = 1;
int pbIn = 0;
int pin3 = 3;
int pin2 = 2;
int pin4 = 4;
void setup ()
{
  pinMode(pin1, OUTPUT);
  attachInterrupt(pbIn, interruptservice, RISING);
  pinMode(pin3, OUTPUT);
  pinMode(pin4, OUTPUT);
  volatile int buttonFlag = 0;
}
  void loop ()
{
    if (buttonFlag == LOW)
    {
        heartbeat ();                        //make led beat
    }
    else
    {
        digitalWrite(pin1, HIGH);         //button stays green once pushed
        delay (1000);        //has some other delays
        digitalWrite(pin1, LOW);
        delay (1000);
        digitalWrite(pin4, HIGH);         //button stays green once pushed
        delay (1000);        //has some other delays
        digitalWrite(pin4, LOW);
        delay (1000);
        buttonFlag = 0;                     //clear flag after executing code
    }

}

void heartbeat ()
{
  digitalWrite(pin3, HIGH);
  delay(500);
  digitalWrite(pin3, LOW);
  delay(500);
}
// Interrupt Service Routine attached to INT0 vector
void interruptservice()
{
    buttonFlag = digitalRead(pin2);    //set flag to value of button
}


I was managed to use the interrupt as a flag, however, is it possible to monitor 4 inputs at the same time in order to use the input to make a function executable at anytime without delay? Thanks in advance

Don't make delay to high. It makes button scanning delay.
You easily can use counter to make the step.

normally after interrupt processor will return the program counter to the previously executing and stopped line of the instructions.